Mechanical Engineering - Thermodynamics - Discussion

Discussion Forum : Thermodynamics - Section 1 (Q.No. 6)
6.
An adiabatic process is one in which
no heat enters or leaves the gas
the temperature of the gas changes
the change in internal energy is equal to the mechanical workdone
all of the above
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
49 comments Page 5 of 5.

Rajkumar said:   1 decade ago
During adiabatic process, heat transfer will not takes place. Then how temperature will change. Answer is wrong.

Prasad said:   1 decade ago
In adiabatic process, no heat transfer takes place. And there, may be a temperature change, and it need not involve nay heat transfer to it. It may occur naturally as well. For eg. I am compressing a cylinder, automatically pressure will rise, so also the temp. Same as reverse.

And dq = -dw.

So answer is correct.

Amit said:   1 decade ago
In this process dQ=0.

If dQ=0.

Then we know dU=dW+dQ.

du=Dw (dQ=0).

Akshay jain said:   1 decade ago
Adiabatic changes in temperature occur due to changes in pressure of a gas while not adding or subtracting any heat.

Bipin said:   1 decade ago
An adiabatic process is constant heat process i.e. not heat transfer will occurs, if there is no heat transfer then how the temperature will change, therefor the answer is wrong as given above.

Mohammad Khurram Saeed said:   1 decade ago
Second law dQ =TdS, dS = 0 for adiabatic process I.e isentropic and irreversible process.
(Constant temperature heat change as the process is quasi static leading to irreversible process).

Hence, dQ = 0.

dQ= dU + dW.

Hence, dU = - dW.

Kshitiz said:   1 decade ago
If temperature of the gas changes then there will be some heat change or transfer, in that case how process will be adiabatic?

Abhishek said:   1 decade ago
Adiabatic process no heat enter and leave system.

So dQ = 0.

Now dQ = dU+dW.

Hence dW = -dU.

Krishan said:   1 decade ago
In adiabatic process no heat enter and lease system then work done by or on the system is zero.

dQ=0 then dW=0 As per first law of thermodynamics.


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