Mechanical Engineering - Thermodynamics - Discussion
Discussion Forum : Thermodynamics - Section 1 (Q.No. 9)
9.
When the gas is heated at constant volume, the heat supplied increases the internal energy of the gas.
Discussion:
27 comments Page 3 of 3.
Anil said:
1 decade ago
No pressure change means no work. In this case heat supplied is =internal energy. From 1st law.
Mani said:
1 decade ago
dq=dw+du, at constant volume dw=0.
So dq=du if dq increases then du also increases.
So dq=du if dq increases then du also increases.
Nagesh said:
9 years ago
According to Maxwell's equation,
dU = TdS - PdV.
So at the constant volume dV = 0.
dU = TdS - PdV.
So at the constant volume dV = 0.
(1)
Sanjeet kumar said:
1 decade ago
As we know that temperature is a function of inernal energy. i.e T= f(U)
Abhishek tiwari said:
1 decade ago
Isochoric process dW = 0.
First law,
dQ = dU+dW,
dQ = dU.
First law,
dQ = dU+dW,
dQ = dU.
Dheeraj said:
10 years ago
dQ = dw+du;
Constant vol: w = 0 then,
dQ = du.
Constant vol: w = 0 then,
dQ = du.
Manoj said:
1 decade ago
But w= pdv is true only for reversible process.
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