Mechanical Engineering - Thermodynamics - Discussion
Discussion Forum : Thermodynamics - Section 1 (Q.No. 9)
9.
When the gas is heated at constant volume, the heat supplied increases the internal energy of the gas.
Discussion:
27 comments Page 3 of 3.
Dr. Aayush Gupta and Dr. Rajkiran Shrivastav said:
1 decade ago
Since we have considered a reversible process and closed system, in which work done = pdv, but at constant volume pdv work done is zero.
By first law of thermodynamics we have,
q = du + w,
therefore q=du.
By first law of thermodynamics we have,
q = du + w,
therefore q=du.
Manoj said:
1 decade ago
But w= pdv is true only for reversible process.
Manpreet said:
1 decade ago
We know work done in constant volume process is zero. So dw - 0
According to first law dw=dq+du.
So that dq=du.
According to first law dw=dq+du.
So that dq=du.
Vaibhav said:
1 decade ago
Constant volume process work done is zero.
i.e. A/C first law of Thermodynamics total heat supplied used for increasing internal energy of system.
i.e. A/C first law of Thermodynamics total heat supplied used for increasing internal energy of system.
Saibabu said:
1 decade ago
Here volume is constant therefore dv=0.
dw = pdv.
dw = 0.
According to first law dQ = du+dw.
dQ = dU.
Therefore if we are giving heat to the system then interna energy will also increase.
dw = pdv.
dw = 0.
According to first law dQ = du+dw.
dQ = dU.
Therefore if we are giving heat to the system then interna energy will also increase.
Aamir Akhtar said:
1 decade ago
As vol is const. W.d = 0.
Therefore net heat supplied is utilised in increasing the internal energy.
Therefore net heat supplied is utilised in increasing the internal energy.
Abhishek tiwari said:
1 decade ago
Isochoric process dW = 0.
First law,
dQ = dU+dW,
dQ = dU.
First law,
dQ = dU+dW,
dQ = dU.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers