Mechanical Engineering - Thermodynamics - Discussion
Discussion Forum : Thermodynamics - Section 1 (Q.No. 9)
9.
When the gas is heated at constant volume, the heat supplied increases the internal energy of the gas.
Discussion:
27 comments Page 3 of 3.
Saibabu said:
1 decade ago
Here volume is constant therefore dv=0.
dw = pdv.
dw = 0.
According to first law dQ = du+dw.
dQ = dU.
Therefore if we are giving heat to the system then interna energy will also increase.
dw = pdv.
dw = 0.
According to first law dQ = du+dw.
dQ = dU.
Therefore if we are giving heat to the system then interna energy will also increase.
Abhishek tiwari said:
1 decade ago
Isochoric process dW = 0.
First law,
dQ = dU+dW,
dQ = dU.
First law,
dQ = dU+dW,
dQ = dU.
Sanjeet kumar said:
1 decade ago
As we know that temperature is a function of inernal energy. i.e T= f(U)
DIMPU SAI KRISHNAN said:
1 decade ago
In constant volume processes, pressure is changing so temperature is also changing if temperature is changing internal energy also change because internal energy is a function of temperature only.
Mani said:
1 decade ago
dq=dw+du, at constant volume dw=0.
So dq=du if dq increases then du also increases.
So dq=du if dq increases then du also increases.
Sumit ghosh said:
1 decade ago
From first law of thermodynamics,
dq= du + dw and dw = pdv.
At constant volume dw = 0.
So, dq = dw.
dq= du + dw and dw = pdv.
At constant volume dw = 0.
So, dq = dw.
Hare ram said:
1 decade ago
In constant volume processes the volume remains const. The internal energy=m*cv* (change in temp) , the final temp is raising automatically internal energy increases.
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