Mechanical Engineering - Theory of machines - Discussion

Discussion Forum : Theory of machines - Section 1 (Q.No. 3)
3.
In a vibrating system, if the actual damping coefficient is 40 N/m/s and critical damping coefficient is 420 N/m/s, then logarithmic decrement is equal to
0.2
0.4
0.6
0.8
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
27 comments Page 2 of 3.

Hari prasad said:   5 years ago
I don't understand can anyone explain in a simple way of method?
(3)

Pranay mishra said:   8 years ago
I am not getting this, Explain it simple way, please.
(1)

Peviks said:   9 years ago
Thank you all, it great to understand the solution.

Mech HOD said:   8 years ago
LD = 2 x π x 40 / sqrt(420^2-40^2) = 0.601.
(2)

Vicky pooraneeswar said:   9 years ago
Can anyone please explain in a simple way?

Ramu said:   9 years ago
Zeta is damping factor or damping ratio.

Rohit said:   9 years ago
May be Zeta is the damping coefficient.

The SARK said:   1 decade ago
2*pi*(40/420)*(1-(40/420)^2) = 0.59.

Mohan said:   9 years ago
Good explanation. Thank you all.

Yas said:   1 decade ago
2*pi*(40/440)/sqrt(1-(40/440)^2.


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