Mechanical Engineering - Theory of machines - Discussion
Discussion Forum : Theory of machines - Section 1 (Q.No. 3)
3.
In a vibrating system, if the actual damping coefficient is 40 N/m/s and critical damping coefficient is 420 N/m/s, then logarithmic decrement is equal to
Discussion:
27 comments Page 2 of 3.
Rohit said:
9 years ago
May be Zeta is the damping coefficient.
Ramu said:
9 years ago
Zeta is damping factor or damping ratio.
Vicky pooraneeswar said:
9 years ago
Can anyone please explain in a simple way?
Jithin said:
9 years ago
@Vicky.
Just find logarithmic decrement using following equation.
Logarithmic Decrement = 2 * (Pi) * Zeta/sqrt(1-zeta^2).
Where zeta is ratio of Actual damping coefficient/Critical damping coefficient.
Just find logarithmic decrement using following equation.
Logarithmic Decrement = 2 * (Pi) * Zeta/sqrt(1-zeta^2).
Where zeta is ratio of Actual damping coefficient/Critical damping coefficient.
Kareena shah said:
9 years ago
Perfect answer @Jithin.
Mohan said:
9 years ago
Good explanation. Thank you all.
Nagamalleswarao said:
9 years ago
Could you please confirm the zeta. Is this zeta is a damping factor or damping coefficient, or both are same?
Mech HOD said:
8 years ago
LD = 2 x π x 40 / sqrt(420^2-40^2) = 0.601.
(2)
Pranay mishra said:
8 years ago
I am not getting this, Explain it simple way, please.
(1)
Leela said:
8 years ago
Cc=2π40/420 = 0.61.
(3)
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