Mechanical Engineering - Theory of machines - Discussion
Discussion Forum : Theory of machines - Section 1 (Q.No. 3)
3.
In a vibrating system, if the actual damping coefficient is 40 N/m/s and critical damping coefficient is 420 N/m/s, then logarithmic decrement is equal to
Discussion:
27 comments Page 2 of 3.
Nagamalleswarao said:
9 years ago
Could you please confirm the zeta. Is this zeta is a damping factor or damping coefficient, or both are same?
Mohan said:
9 years ago
Good explanation. Thank you all.
Kareena shah said:
9 years ago
Perfect answer @Jithin.
Jithin said:
9 years ago
@Vicky.
Just find logarithmic decrement using following equation.
Logarithmic Decrement = 2 * (Pi) * Zeta/sqrt(1-zeta^2).
Where zeta is ratio of Actual damping coefficient/Critical damping coefficient.
Just find logarithmic decrement using following equation.
Logarithmic Decrement = 2 * (Pi) * Zeta/sqrt(1-zeta^2).
Where zeta is ratio of Actual damping coefficient/Critical damping coefficient.
Vicky pooraneeswar said:
9 years ago
Can anyone please explain in a simple way?
Ramu said:
9 years ago
Zeta is damping factor or damping ratio.
Rohit said:
9 years ago
May be Zeta is the damping coefficient.
Peviks said:
9 years ago
Thank you all, it great to understand the solution.
Pradeep said:
9 years ago
What is zeta?
Swagat said:
9 years ago
Thanks for all you explanation.
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