Mechanical Engineering - Theory of machines - Discussion

P=(Tmax-Tc)*k*V.
If Tc=0, P is max.
If Tc#0, P is decreased.

It should decrease the power transmitted.

However, at very high belt speeds (usually above 1500 m/min) , power decreases with increasing belt speed due to rapid rise of centrifugal force acting the belt. This centrifugal force reduces the pressure between the belt and the rim of the pulleys, moving the belt away from the pulley, reducing the wrap angle and hence, the belt tensions and power transmission.

It reduces the power transmission.

It doesn't affect power transmission.
Power = (T1-T2)V.

Considering centrifugal tension
T1 = T1 + TC.
T2 = T2 + TC.
Power = ((T1+TC) - (T2+TC))V
= (T1-T2)V.

@Krishna.

Correct explanation, Thanks.

It doesn't affect power transmission.

Power = (Tt-Ts)V.
Considering centrifugal tension.
Tt = T1 + TC. = tight side tension.
Ts = T2 + TC. = slack side tension.
Power = ((T1+TC) - (T2+TC))V.
= (T1-T2)V.

Usually, power transmission is proportional to belt speed.

However, at very high belt speeds which are usually above 1500 m/min, the power decreases with increase in the belt speed due the to rapid rise of centrifugal force acting on the belt. This centrifugal force reduces the pressure between the belt and the rim of the pulleys, and thus, move the belt away from the pulley and reduce the wrap angle. Therefore, the belt tensions and power transmission also are reduced.

It's (T1-Tc) xV.

It's (T1-Tc) xV.