Mechanical Engineering - Theory of machines - Discussion
Discussion Forum : Theory of machines - Section 9 (Q.No. 13)
13.
ABCD is a four bar mechanism in which AB = 310 mm and CD = 450 mm. AB and CD are both perpendicular to the fixed link AD, as shown in the below figure. If the velocity of B at this condition is v. Then the velocity of C is
v
v
v
vDiscussion:
20 comments Page 2 of 2.
Shrivardhan said:
6 years ago
A is correct answer as per ACE notes.
Anuj said:
6 years ago
A is the correct answer. I too agree.
Kiran said:
7 years ago
Option A is the correct answer. Since crank and rocker are parallel to each other the coupler angular velocity becomes zero. So, Vb=Vc.
Ramesh said:
7 years ago
Yes, A is the correct answer.
Kais said:
8 years ago
I believe A is the correct answer as both vB and Vc are horizontal and link BC can not be rotating so has no contribution to the velocity of vC/A; That is, w3 = 0 (or VCA=0). You may also use instantaneous center I24 and find the relationship between w2 and w4, they are proportional with w2/w4=CD/AB so vB=Vc.
JKVERMA37 said:
8 years ago
A is right option, because in condition link BC is in pure translation.
Som said:
9 years ago
{45 ÷ 31} * v = (3/2)v.
Abhi said:
9 years ago
I think the answer is A, as we draw a velocity diagram it will be a straight line, where B nd C coincide. So, Vb = Vc.
I have a question @G Nagaraju.
Why have you taken the angular velocity of both same?
I have a question @G Nagaraju.
Why have you taken the angular velocity of both same?
G Nagaraju said:
1 decade ago
Vc/Vb = CD/AB.
= 450/310 AB distance is 300 it will perfectly come.
= 1.46 ~ 1.5.
= 1.5 = 3/2.
Vc = Vb*3/2.
= 3/2 Vb.
= 450/310 AB distance is 300 it will perfectly come.
= 1.46 ~ 1.5.
= 1.5 = 3/2.
Vc = Vb*3/2.
= 3/2 Vb.
(1)
Gaurav said:
1 decade ago
How is it calculated?
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