Mechanical Engineering - Strength of Materials - Discussion

Discussion Forum : Strength of Materials - Section 1 (Q.No. 20)
20.
A thin cylindrical shell of diameter (d) and thickness (t) is subjected to an internal pressure (p). The ratio of longitudinal strain to volumetric strain is
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
20 comments Page 2 of 2.

Kiran said:   10 years ago
Longitudinal strain : Volumetric strain.

[(pd/4Et)(1-2v)] : [(pd/4Et)(5-4v)].

(1-2v) : (5-4v).

V[(1/v)-2] : v[(5/v)-4].

Where, (1/v) = m.

(m-2):(5m-4).

Siva katuri said:   10 years ago
Longitudinal strain : pr/[2tE (1-2/m)].

Volumetric strain : pr/[2tE (5-4/m)].

pr/[2tE (1-2/m)] : pr/[2tE (5-4/m)].

pr/pr : 2tE (1-2/m) / 2tE (5-4/m).

: 2tE[ (m-2) /m]/2tE[(5m-4)/m].

: [(m-2)/m]/[(5m-4)/m].

: (m-2)/(5m-4).

Sachin said:   1 decade ago
@Abhishek.

No answer is correct!

m is not Poisson's ratio. Its reciprocal is

m = (1/u).

Long strain = (PR/2tE)(1-2/m).

Vol strain = (PR/2tE)(5-4/m).

Abhishek said:   1 decade ago
All options are wrong.

Longitudinal strain = pr/2tE(1-2m).

Volumetric strain = pr/2tE(5-4m).

Harish said:   1 decade ago
Prove that clearly?

Vikas said:   1 decade ago
Net longitudinal strain = pd/4tE(1-2/m).

Net volumetric strain = pdV/2tE(5/2-2/m).

Manoj prasad said:   1 decade ago
fl = Longitudinal stress.
fc = Volumetric stress.

Longitudinal strain = el = fl/E-(1/m)*((fc)/E).
Volumetric strain = ec = fc/E - (1/m)*((fl)/E).

Now,
Longitudinal strain/volumetric strain.

Solve it & you will get the answer as (D).

Shubham81 said:   1 decade ago
How its?

Emlin said:   1 decade ago
1/m is poisson's ratio where m is a constant. Values ranging between 3 and 4.

Ash said:   1 decade ago
What is m?


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