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Mechanical Engineering - Strength of Materials - Discussion

Discussion Forum : Strength of Materials - Section 2 (Q.No. 7)
Strength of Materials
7.
When a thin cylindrical shell is subjected to an internal pressure, there will be
a decrease in diameter and length of the shell
an increase in diameter and decrease in length of the shell
a decrease in diameter and increase in length of the shell
an increase in diameter and length of the shell
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
14 comments Page 2 of 2.
Balaji said:   7 years ago
Pd/4t is the formula for a thin cylindrical shell. So, p is directly proportional to d wherever d=2l.
(1)
Kar tariq said:   7 years ago
When a thin shell is subjected to an internal pressure. Hoop stress developed is tensile therefore increase in dia also. Longitudinal stress developed is a tensile therefore increase in length also. So the correct answer is Option D.
(2)
Harshad patel said:   6 years ago
Good explanation, thanks @Nainesh.
Shubham jalan said:   5 years ago
Thanks for explaining @Kar Tariq.
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