Mechanical Engineering - Strength of Materials - Discussion

Discussion Forum : Strength of Materials - Section 1 (Q.No. 8)
8.
Two shafts 'A' and 'B' transmit the same power. The speed of shaft 'A' is 250 r.p.m. and that of shaft 'B' is 300 r.p.m. The shaft 'B' has the greater diameter.
True
False
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
52 comments Page 3 of 6.

Sunny said:   1 decade ago
P = TW.
T = PI*DN/60.
D = 1/N.

Diameter is inversely proportional to Rpm.

Govind.T said:   1 decade ago
There is direct relation.

Power(P) = Torque(t)*Angular velocity(w).

(shear stress(s) = 16t/(3.14*d^3).

(w = 2*3.14*n/60).

= s*pi (3.14)*d^3*2*pi*n/60.

Power is directly proportional to d^3 and r.p.m(n).

To get same power for less r.p.m shaft it should have more diameter.

Daya said:   1 decade ago
Is diameter of shaft is directly proportional to speed?

Vikash said:   1 decade ago
Speed of shaft and its diameter both are inversely depends on so, less diameter have more speed.

Suresh said:   1 decade ago
Dia is inversely proportional of speed.

Neeraj chauhan said:   1 decade ago
Because velocity V = r*omega.

v = D/2*omega.

So v = D/2*2*pi*n.

D*n = v.

Now D is inversely proportional to n. So more R.P.M less diameter.

Ajit Mhetre said:   1 decade ago
Speed of shaft is inversely proportional to its diameter.

Dilip sharma said:   1 decade ago
(n1/n2)/(t2/t1).

Vinoth said:   1 decade ago
If diameter of shaft increases means speed will decreases, on other hand, Torque will increases.

Nemish said:   10 years ago
Power = Inertia*Angular velocity.

If angular velocity is increased, I would decrease to maintain same power.


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