Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 8)
8.
Two shafts 'A' and 'B' transmit the same power. The speed of shaft 'A' is 250 r.p.m. and that of shaft 'B' is 300 r.p.m. The shaft 'B' has the greater diameter.
Discussion:
52 comments Page 2 of 6.
Dilip sharma said:
1 decade ago
(n1/n2)/(t2/t1).
Neeraj chauhan said:
1 decade ago
Because velocity V = r*omega.
v = D/2*omega.
So v = D/2*2*pi*n.
D*n = v.
Now D is inversely proportional to n. So more R.P.M less diameter.
v = D/2*omega.
So v = D/2*2*pi*n.
D*n = v.
Now D is inversely proportional to n. So more R.P.M less diameter.
Vinoth said:
1 decade ago
If diameter of shaft increases means speed will decreases, on other hand, Torque will increases.
Nemish said:
10 years ago
Power = Inertia*Angular velocity.
If angular velocity is increased, I would decrease to maintain same power.
If angular velocity is increased, I would decrease to maintain same power.
Univ said:
9 years ago
The speed(rpm) is inversely proportional to Diameter of shaft.
we know
P = (2 * 3.14 * N * T)/60 and also for shaft T = F * radius.
From this, we can observe the answer.
we know
P = (2 * 3.14 * N * T)/60 and also for shaft T = F * radius.
From this, we can observe the answer.
Nikhil Agrawal said:
9 years ago
Speed is inversely proportional to the torque.
So, as the speed of 2nd shaft is more than the 1st shaft so its diameter will be than that of 1st with speed less than 2nd.
So, as the speed of 2nd shaft is more than the 1st shaft so its diameter will be than that of 1st with speed less than 2nd.
Debashish said:
9 years ago
When power is constant then torque is inversely proportional to speed so when speed increase torque is decreased. Again torque is directly proportional to radius from eqn T = f * r. So less torque has less diameter also.
Sushant(dada) Patil said:
9 years ago
Speed is inversly proportional to diameter so shaft of greater daimeter should have less speed than that of smaller one.
Prashant Sabale said:
9 years ago
Lager the diameter less speed and vice versa.
Nilesh said:
9 years ago
Hihow can we calculate stress and strain?
If you know the voltage of motor and rpm and torque. Using this formula if the shaft is made up of ms steel and it is 380gpa. Please tell me.
If you know the voltage of motor and rpm and torque. Using this formula if the shaft is made up of ms steel and it is 380gpa. Please tell me.
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