Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 3)
3.
The neutral axis of the cross-section a beam is that axis at which the bending stress is
Discussion:
41 comments Page 2 of 5.
Nagenendra singh said:
10 years ago
Because bending stress is proportional to distance between neutral point and outer fiber of beam. At neutral point its distance became zero so stress will be zero.
Navin chandra said:
1 decade ago
Definition of the neutral axis itself says that "It is the axis on the plane of cross section, where strain, and hence stress is zero at the time of bending."
Rahul said:
6 years ago
The answer is zero because it is designed in such a way that it can withstand maximum load up to this neutral axis face zero force.
Thank you.
Thank you.
(3)
Debiprasad said:
8 years ago
We know that, bending stress=M/Z.
Aat neutral axis Z=0,
So bending stress is zero.
Here 'Z' is the second moment of inertia=I/Y,
and Y=D/2.
Aat neutral axis Z=0,
So bending stress is zero.
Here 'Z' is the second moment of inertia=I/Y,
and Y=D/2.
KUNDAN said:
10 years ago
Applied load is crosses or on perpendicular to the neutral axis of beam. So BM is zero also the shear force is also zero.
Ikwu Anthony said:
8 years ago
Because at the neutral axis, there is no effect of load and therefore there is no stress at the neutral axis.
Aamir said:
8 years ago
As bending stress =MY/I, where y is the distance of extreme fibre from NA.
So at NA y=0 ,therefore BS =0.
So at NA y=0 ,therefore BS =0.
(1)
Shetty said:
1 decade ago
The force acting on beam it tends to bend the body but there no affect on the neutral axis so its zero.
Ashish said:
10 years ago
Line or plane through a beam at which there is no extension or compression occurs when the beam bends.
Sumanta dey said:
8 years ago
Because of shear stress maximum in N.A. So bending stress is min in N. A. And maxi in extreme fibre.
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