Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 2 (Q.No. 29)
29.
For the beam shown in the below figure, the shear force at A is equal to
Discussion:
32 comments Page 4 of 4.
Manoj badu said:
5 years ago
F (a)+Fb=wl/2.
M (b)=0.
Then, Fa*l-wl/2*2l/3=0.
We get Fa=wl/3.
And Fb=wl/2-wl/3=wl/6.
M (b)=0.
Then, Fa*l-wl/2*2l/3=0.
We get Fa=wl/3.
And Fb=wl/2-wl/3=wl/6.
Vinay BEL said:
5 years ago
wl/3 is right. I agree.
(1)
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