Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 3 (Q.No. 22)
22.
If the modulus of elasticity of a material is twice its modulus of rigidity, then the Poisson's ratio of the material is equal to zero.
Discussion:
13 comments Page 2 of 2.
Srikanth said:
9 years ago
Thank you @Rathi & @Krunal.
Krunal said:
1 decade ago
Here equation is:
G = vE/(2(1+v)).
1+v = v2G/2G.
1+v = v.
(1/v)+1 = 1.
1/v = 0 or v = 0.
G = vE/(2(1+v)).
1+v = v2G/2G.
1+v = v.
(1/v)+1 = 1.
1/v = 0 or v = 0.
Rathi said:
1 decade ago
G = E/(2(1+ v)).
Where G is the rigidity modulus.
E is the Young's modulus(modulus of elasticity) and
v is the Poisson's ratio.
Acc. to the question,
G = 2G/(2(1+v)).
(1+v) = 2G/2G.
1+v = 1.
v = 0.
Where G is the rigidity modulus.
E is the Young's modulus(modulus of elasticity) and
v is the Poisson's ratio.
Acc. to the question,
G = 2G/(2(1+v)).
(1+v) = 2G/2G.
1+v = 1.
v = 0.
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