Mechanical Engineering - Hydraulics and Fluid Mechanics - Discussion
Discussion Forum : Hydraulics and Fluid Mechanics - Section 8 (Q.No. 14)
14.
The density of a liquid in kg/m3 is numerically equal to its specific gravity.
Discussion:
23 comments Page 2 of 3.
GAURAV said:
6 years ago
I agree with Rn Singh. Both are numerically same and answer is correct.
RN singh said:
6 years ago
Specific Gravity and relative density are not the same but, numerically equal.
So, Answer is B.
So, Answer is B.
Fakhre Alam said:
1 decade ago
In the metric system the density of water at 4°C is 1.00 g/cm3 (or 1.00 g/mL), 3 equivalent to 1000 kg/m3, and hence the specific gravity (which is dimensionless) of a liquid has the same numerical value as its density expressed in g/mL or Mg/m3.
Jayesh mali said:
7 years ago
I think this answer is true only in the case of water not for other fluid.
Saurabh chauhan said:
7 years ago
@Brij Kishor
The statement is wrong.
The Density of liquid = its specific gravity.--> False.
The density of liquid = its specific gravity * 1000--> True.
The statement is wrong.
The Density of liquid = its specific gravity.--> False.
The density of liquid = its specific gravity * 1000--> True.
Deepak maheshwari said:
8 years ago
Statement is incorrect.
For example.
If you consider the mass density of water equal to 1000 kg/m3. Then specific gravity of water is equal to 1.
But 1 is not equal to 1000.
If you consider mass density in gm / cm3 which is 1 gm/cm3 for water then specific gravity is also 1.
1=1.
So the statement is correct for only unit gm/cm3.
The statement is not correct for unit KN/m3.
For example.
If you consider the mass density of water equal to 1000 kg/m3. Then specific gravity of water is equal to 1.
But 1 is not equal to 1000.
If you consider mass density in gm / cm3 which is 1 gm/cm3 for water then specific gravity is also 1.
1=1.
So the statement is correct for only unit gm/cm3.
The statement is not correct for unit KN/m3.
Neeraj said:
8 years ago
Its false.
Brij kishor said:
8 years ago
As density of water is also equal to 1000 kg/m^3.
So,
Density of a liquid = ( specific gravity )( 1000 kg/m^3 )
Density of a liquid = specific gravity in 1000 kg/m^3.
in this way the given statement is true.
So,
Density of a liquid = ( specific gravity )( 1000 kg/m^3 )
Density of a liquid = specific gravity in 1000 kg/m^3.
in this way the given statement is true.
Muhammad Waqas said:
9 years ago
You are right @Shail.
The statement should be like, The density of a liquid in g/cm^3 is numerically equal to its specific gravity. Why?
Specific gravity = density of a liquid / density of water...............(i)
Rearranging the equation.
Density of a liquid = (specific gravity)(density of water).
As density of water = 1 g/cm^3.
So,
Density of a liquid = (specific gravity)(1 g/cm^3).
Density of a liquid = specific gravity in g/cm^3.
Proved
The statement should be like, The density of a liquid in g/cm^3 is numerically equal to its specific gravity. Why?
Specific gravity = density of a liquid / density of water...............(i)
Rearranging the equation.
Density of a liquid = (specific gravity)(density of water).
As density of water = 1 g/cm^3.
So,
Density of a liquid = (specific gravity)(1 g/cm^3).
Density of a liquid = specific gravity in g/cm^3.
Proved
Dhaval said:
9 years ago
The answer should be False.
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