Mechanical Engineering - Engineering Mechanics - Discussion

Discussion Forum : Engineering Mechanics - Section 1 (Q.No. 16)
16.
Moment of inertia of a triangular section of base (b) and height (h) about an axis passing through its C.G. and parallel to the base, is
bh3/4
bh3/8
bh3/12
bh3/36
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
16 comments Page 2 of 2.

Shehab zakaria said:   8 years ago
Why 1/3?

Dinesh said:   7 years ago
The Center of gravity lies at 1/3 rd of height from base.

Rohan said:   7 years ago
What is the moment of inertia of triangle at its apex?

Ajeya said:   7 years ago
How bh^3/36? Please explain me to understand it.

Srinidhi said:   5 years ago
Can someone explain in detail?

Fawi said:   5 years ago
CG point 1,2.

So CG from the base: 1/3.
So, 1/12 * 1/3 = 1/36.


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