Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 1 (Q.No. 16)
16.
Moment of inertia of a triangular section of base (b) and height (h) about an axis passing through its C.G. and parallel to the base, is
Discussion:
16 comments Page 2 of 2.
Shehab zakaria said:
8 years ago
Why 1/3?
Dinesh said:
7 years ago
The Center of gravity lies at 1/3 rd of height from base.
Rohan said:
7 years ago
What is the moment of inertia of triangle at its apex?
Ajeya said:
7 years ago
How bh^3/36? Please explain me to understand it.
Srinidhi said:
5 years ago
Can someone explain in detail?
Fawi said:
5 years ago
CG point 1,2.
So CG from the base: 1/3.
So, 1/12 * 1/3 = 1/36.
So CG from the base: 1/3.
So, 1/12 * 1/3 = 1/36.
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