Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 5 (Q.No. 31)
31.
The centre of gravity of a quadrant of a circle lies along its central radius (r) at a distance of
Discussion:
12 comments Page 2 of 2.
Manish said:
8 years ago
CG IN Y AXIS =4R/3π.
THEN CG ALONG R =(4R/3π)/SINE45°.
=.6R.
X, Y AND R CREATE A TRIANGLE IN QUADRANT CIRCLE.
THEN CG ALONG R =(4R/3π)/SINE45°.
=.6R.
X, Y AND R CREATE A TRIANGLE IN QUADRANT CIRCLE.
Diptangshu said:
7 years ago
Actually, it is the diagonal of the square made by the CGs in X and Y direction. That's why the radial distance of the CG from the centre will be the length of the diagonal of the square that is 2x(4r/3π)=0.6r.
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