Mechanical Engineering - Engineering Mechanics - Discussion

Discussion Forum : Engineering Mechanics - Section 5 (Q.No. 31)
31.
The centre of gravity of a quadrant of a circle lies along its central radius (r) at a distance of
0.5r
0.6r
0.7r
0.8r
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
12 comments Page 2 of 2.

Hardik said:   5 years ago
The center of gravity of a circular sector making semi-vertical angle α is at a distance of (2/3) are. Sinα/α from the center of the sector measured along the central axis.

2a=90.
A=45.
C.G=0.599999.
(1)

Vinay BEL said:   5 years ago
Simple if CG of the semicircle is 4r/3π.

Then quadrant vl b 4r/6π = 0.6r.
(1)


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