Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 5 (Q.No. 31)
31.
The centre of gravity of a quadrant of a circle lies along its central radius (r) at a distance of
Discussion:
12 comments Page 2 of 2.
Hardik said:
5 years ago
The center of gravity of a circular sector making semi-vertical angle α is at a distance of (2/3) are. Sinα/α from the center of the sector measured along the central axis.
2a=90.
A=45.
C.G=0.599999.
2a=90.
A=45.
C.G=0.599999.
(1)
Vinay BEL said:
5 years ago
Simple if CG of the semicircle is 4r/3π.
Then quadrant vl b 4r/6π = 0.6r.
Then quadrant vl b 4r/6π = 0.6r.
(1)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers