Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 1 (Q.No. 3)
3.
Two balls of equal mass and of perfectly elastic material are lying on the floor. One of the ball with velocity v is made to struck the second ball. Both the balls after impact will move with a velocity
Discussion:
70 comments Page 7 of 7.
Ramana said:
1 decade ago
Two balls are same mass and same nature with the contact motion so each one have half of the original velocity.
Manohar said:
1 decade ago
Total momentum before and after collision is constant. Hence,
m(v+0) = m(v'+v').
mv = 2mv'.
v' = v/2.
m(v+0) = m(v'+v').
mv = 2mv'.
v' = v/2.
Pabitra said:
1 decade ago
Total velocity =v.
Velocity distributed uniformly that = v.
2 ball each has v/2.
Velocity distributed uniformly that = v.
2 ball each has v/2.
Aditya said:
1 decade ago
The body transfer the whole energy to second body because e=1. So first body comes to rest. Another one moves velocity v.
Raghavendra said:
1 decade ago
The velocity will be transferred from the 1st body to the second.
Saurabh said:
1 decade ago
One of the body which was moving initially with velocity V would come to rest and second body will move with velocity v.
Shiva rao said:
1 decade ago
Velocity distributed uniformly.
Kumar srinu said:
1 decade ago
Perfectly elastic materials e (coefficient of restitution) =1.
Shrikant said:
1 decade ago
Two balls of equal mass and of perfectly elastic material are lying on the floor. One of the ball with velocity v is made to struck the second ball. Both the balls after impact will move with a velocity.
Divya said:
1 decade ago
Conservation of momentom
mv=m1v1+m2v2
mv=mv`+mv`
v`=v/2
mv=m1v1+m2v2
mv=mv`+mv`
v`=v/2
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