Mechanical Engineering - Engineering Mechanics - Discussion

Discussion Forum : Engineering Mechanics - Section 1 (Q.No. 3)
3.
Two balls of equal mass and of perfectly elastic material are lying on the floor. One of the ball with velocity v is made to struck the second ball. Both the balls after impact will move with a velocity
v
v/2
v/4
v/8
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
70 comments Page 5 of 7.

Vinoth said:   1 decade ago
Total mass = mv'+mv'.

mv = mv'+mv'.

v = 2v'.

And:v' = v/2.

Abhishek said:   1 decade ago
The first ball which was moving with velocity will become in rest and this velocity is transferred to the second ball and it will start moving with velocity we. So, none of the option is correct.

Sandeep said:   1 decade ago
After hitting both transfer there energy to move v/2.

Gaurav Maini said:   1 decade ago
You are right guyz. It will follow conservation of momentum. But if it is perfectly elastic then the 1st ball should come at rest after colliding with the 2nd one. That means final velocity of 2nd ball will change from 0 to V. How it is v/2? Maybe I'm missing something. Please correct me guyz.

K. srinivasan said:   1 decade ago
We know,

Momentum before collision is equal to momentum after collision for that,

mv + m(0) = mv' + mv'.

mv = m(2v').

So velocity after impact v' = v/2.

Manohar said:   1 decade ago
Total momentum before and after collision is constant. Hence,

m(v+0) = m(v'+v').

mv = 2mv'.

v' = v/2.

Pabitra said:   1 decade ago
Total velocity =v.

Velocity distributed uniformly that = v.

2 ball each has v/2.

Aditya said:   1 decade ago
The body transfer the whole energy to second body because e=1. So first body comes to rest. Another one moves velocity v.

Raghavendra said:   1 decade ago
The velocity will be transferred from the 1st body to the second.

Saurabh said:   1 decade ago
One of the body which was moving initially with velocity V would come to rest and second body will move with velocity v.


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