Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 1 (Q.No. 3)
3.
Two balls of equal mass and of perfectly elastic material are lying on the floor. One of the ball with velocity v is made to struck the second ball. Both the balls after impact will move with a velocity
Discussion:
70 comments Page 4 of 7.
Parth said:
1 decade ago
Its wrong, only V2 has velocity of V after impact.
Dinesh said:
1 decade ago
After striking the velocity of the two bodies will be reduces why because assume both the two bodies are rotate in CW direction when second body front side touches the first body back side due to same direction speed will be reduces.
RaviTeja Reddy said:
1 decade ago
Law of conservation of momentum.
Sumeet said:
1 decade ago
Law of conservation of momentum.
When one ball hits second then the first ill stop & its momentum is transfer to other with the half of the velocity of first ball.
That's why answer = V/2.
When one ball hits second then the first ill stop & its momentum is transfer to other with the half of the velocity of first ball.
That's why answer = V/2.
Sanket haste said:
1 decade ago
Initial velocity = v.
Given condition that both balls are moving.
Hence v/2.
Given condition that both balls are moving.
Hence v/2.
Jay said:
1 decade ago
For two perfectly elastic body, the velocity after collided become same i.e. velocity 1st ball after collide equal to velocity of 2nd ball after collide.
So final velocity of the ball half of the initial velocity. It will get from the equation of conservation of momentum after and before.
So final velocity of the ball half of the initial velocity. It will get from the equation of conservation of momentum after and before.
Vivek kumar singh ideal ghaziabad said:
1 decade ago
According to question balls is perfectly elastic material then the total energy of first ball is transfer to second ball after collision then first ball energy less it means no energy no movement then the velocity of first ball is 0 and second ball is travel of velocity v.
Deepak said:
10 years ago
The total energy of momentum of force is directly impact v = 1/v, it is impact force.
Uzzal said:
9 years ago
mv1_+mv2 = mv'1+mv'2.
m is equal.
v1+0 = 2v' because v1 = 0 and v'1 = v'2.
v' = v/2.
m is equal.
v1+0 = 2v' because v1 = 0 and v'1 = v'2.
v' = v/2.
Madheswaran BIT said:
9 years ago
Velocity after striking will be v/2.
Because it is a perfectly elastic body so after striking both are will move in an opp direction so by applying momentum equation.
Total momentum before striking = Total momentum After strike.
m(v1i+v2i) = m(v1f+v2f).
@ first V2i = 0.
mV = m(v1+V2) Perfectly elastic so V1f=V2F.
V=2Vf.
V(final)=V/2.
Because it is a perfectly elastic body so after striking both are will move in an opp direction so by applying momentum equation.
Total momentum before striking = Total momentum After strike.
m(v1i+v2i) = m(v1f+v2f).
@ first V2i = 0.
mV = m(v1+V2) Perfectly elastic so V1f=V2F.
V=2Vf.
V(final)=V/2.
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