Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 1 (Q.No. 3)
3.
Two balls of equal mass and of perfectly elastic material are lying on the floor. One of the ball with velocity v is made to struck the second ball. Both the balls after impact will move with a velocity
Discussion:
70 comments Page 3 of 7.
Sumeet said:
1 decade ago
Law of conservation of momentum.
When one ball hits second then the first ill stop & its momentum is transfer to other with the half of the velocity of first ball.
That's why answer = V/2.
When one ball hits second then the first ill stop & its momentum is transfer to other with the half of the velocity of first ball.
That's why answer = V/2.
Akif said:
5 years ago
In pool tables, though they aren't perfectly elastic, there can be a few results. So, we can assume for a situation where both the balls have the same velocity v/2 would be their velocity.
(1)
Tom said:
1 decade ago
The first ball will be at rest and the second will have a velocity v unless the collision angle is not zero, then in a certain angle of collision the two balls will have the same velocity.
AJEESH said:
7 years ago
This is considered as inelastic collision so both will move in same velocity, V/2, If the collision was in the vacuum, ie perfectly elastic collision, V1F will be 0 and V2F will be V.
Sakthivel said:
8 years ago
Conservation of momentum
Consider
U-initial velocity
V-final velocity
m1u1+m2u2=m1v1+m2v2
m(u1+0)=m1(v1+v2)
u1=v1+v2
Therefore finial velocity equally distributed
So u=2v.
V=u/2.
Consider
U-initial velocity
V-final velocity
m1u1+m2u2=m1v1+m2v2
m(u1+0)=m1(v1+v2)
u1=v1+v2
Therefore finial velocity equally distributed
So u=2v.
V=u/2.
Suraj said:
8 years ago
@ALL.
It is the fact is it is a perfectly elastic collision so no kinetic energy losses. So the velocity of the 1st body will transfer to next body. And the answer will be V.
It is the fact is it is a perfectly elastic collision so no kinetic energy losses. So the velocity of the 1st body will transfer to next body. And the answer will be V.
MITHUN KUMAR BISWAS said:
7 years ago
I think it would be v/√2.
If the second body before struck were in rest. Must answer should be v/√2. (kinetic energy should be equal before and after collision).
If the second body before struck were in rest. Must answer should be v/√2. (kinetic energy should be equal before and after collision).
Vikas.g said:
1 decade ago
Velocity of first moving ball is v after impact its velocity becomes half therefor every action the is equal and opposite reaction so velocity of 2nd ball is also v/2.
Santhosh.M.R said:
1 decade ago
Two balls have same mass and elastic property.
So e = 1,
Momentum before impact = momentum after impact.
mv+m*0 = mv1+mv1 {after impact v1 = v2}.
Hence, v1 = v/2.
So e = 1,
Momentum before impact = momentum after impact.
mv+m*0 = mv1+mv1 {after impact v1 = v2}.
Hence, v1 = v/2.
Sohan said:
9 years ago
After impact, the ball 1 will come into rest and 2 will move with velocity we.
What you guys are saying that happens only if the collision is perfectly plastic?
What you guys are saying that happens only if the collision is perfectly plastic?
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