Mechanical Engineering - Engineering Mechanics - Discussion

Discussion Forum : Engineering Mechanics - Section 1 (Q.No. 8)
8.
The angle of inclination of a vehicle when moving along a circular path __________ upon its mass.
depends
does not depend
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
38 comments Page 2 of 4.

Jagrut said:   8 years ago
Because of object moved on circular path.
So equation of angle is,
Angle = w*t.
So does not depend on mass.

Jayesh Dhotkar said:   8 years ago
In case, if the angle of inclination of the vehicle.

I think mass of vehicle doesn't matter if it is moving in circular path because it's depends on speed of vehicle.

Prathap said:   8 years ago
It depends on velocity of the vehicle.

Monex sharma said:   8 years ago
Acceleration for a circular motion is v^2/r, so not dependent on mass. Acceleration from gravity isn't either. The angle is just the angle of the vector sum of these two accelerations.

Ajay Gupta said:   9 years ago
Tan$ = v square/rg,
Where, v = velocity, g = gravity. So there is no depandent in mass.

Rohit said:   9 years ago
A common eg : Mout ka Kuan (Well of Death).

Car and bike both rotate in the speed are same.

But the mass of the car is greater than the bike.

B'coz It only depends on speed.

Ammar Mubarak Maar said:   9 years ago
Three forces creating torques are affecting on the car in and make the car balanced without rolling. centrifugal force Fc wich depeds on the mass and velosity and radius of the curve. The other tow is the wieght (W) which depends on the mass and the gravitational accelleration and the spring force Fs (the car is suspended on the chasis via springs) whcih depends on the change in the height of the spring that proportional to tan($) ($) is the inclination angle. Putting all in equation.

Fc * h = W * n + Fs * x --------------(1)

Fc = Mass * V^2/R --------------(2)
W = Mass* G --------------------(3)
Fs = (Spring Constant c) * (Change in spring hight L) -------------(4)
(Change in spring hight L) is proportional to tan($) where $ is the inclination angle.

Then from equation (4):
Fs = c * c2 * tan($) ----------------(5)

Using Equations 1, 2, 3 & 5:

Mass * V^2/R * h = Mass * G * n + c * c2 * x * tan($)

Hence:
tan($) = Mass * (V^2/R * h - G * n) / ( c * c2 * x ) ---------------------(6)

So it is clear that the inclination angle depends on the mass and velocity of the car.

Sharad said:   10 years ago
It should be depends only on velocity. Because when velocity increases centrifugal force increases which tends to vehicle remains in touch with circular path.

Manoj Gupta said:   10 years ago
Angle of inclination depends solely on the radius of curvature of path.

Utkarsh kumar said:   10 years ago
For the vehicle to be in equilibrium overturning couple should be equal to balancing couple acting in clockwise direction due to weight of vehicle and rider.

So its depends on mass.


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