Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 3 (Q.No. 42)
42.
The resultant of the two forces P and Q is R. If Q is doubled, the new resultant is perpendicular to P. Then
Discussion:
12 comments Page 2 of 2.
JahnaNarayan Dhal said:
9 years ago
I can not understand how to find p + 2Qcos0 = 0. Please help me.
Popy said:
1 decade ago
Tan a= Qsin0/P+Qcos0.
When Q is double, then.
Tan90 = 2Qsin0/P+2Qcos0.
We know tan90 = infinity.
P+2Qcos0 = zero.
P = -2Qcos0.
R = root P^2+Q^2+2PQCOS0.
Putting P = -2Qcos0.
R = Q.
When Q is double, then.
Tan90 = 2Qsin0/P+2Qcos0.
We know tan90 = infinity.
P+2Qcos0 = zero.
P = -2Qcos0.
R = root P^2+Q^2+2PQCOS0.
Putting P = -2Qcos0.
R = Q.
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