Mechanical Engineering - Engineering Mechanics - Discussion

Discussion Forum : Engineering Mechanics - Section 1 (Q.No. 10)
10.
If the resultant of two equal forces has the same magnitude as either of the forces, then the angle between the two forces is
30°
60°
90°
120°
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
35 comments Page 3 of 4.

Qamar said:   1 decade ago
Let R = f then,
f^2 = f^2+f^2+2f.fcosa.
-f^2/2f^2 = cosa.
cosa = -1/2.
a = 120.

Sathish said:   1 decade ago
Because two forces and one resultant.

Resultant between two forces.

Himanshu said:   1 decade ago
If the angle would be 120 than only at the mid xcos60+xcos60 = x.

Kiran kumar said:   4 years ago
According to Lamis theorem : p/sinα+q/sinβ+r/sinγ.

Ranga... said:   7 years ago
Two force and one resultant.

Than 360/3-120.

Punith said:   9 years ago
Why 120° why not the answer be 90°?

Krishna said:   1 decade ago
cos(120) = cos(90+30) = -sin30 = -0.5.

Naiya said:   8 years ago
I think we can apply Lami's theorem.

Srinu said:   9 years ago
It is based triangle law of forces.

Ajay said:   8 years ago
Can anyone tell exact explanation?


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