Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 1 (Q.No. 10)
10.
If the resultant of two equal forces has the same magnitude as either of the forces, then the angle between the two forces is
Discussion:
35 comments Page 2 of 4.
Krishna said:
1 decade ago
cos(120) = cos(90+30) = -sin30 = -0.5.
Murali Raj K said:
10 years ago
Both the forces are equal thus the resultant is also equal.
Total angle is 360.
Three forces are acting equally thus 360/3=120.
Total angle is 360.
Three forces are acting equally thus 360/3=120.
Abdul Khaleque said:
10 years ago
p2 = p2+p2+2p.pcosθ.
p2 = 2p2+2p2cosθ.
-p2 = 2p2cosθ.
cosθ = -1/2.
θ = 120.
p2 = 2p2+2p2cosθ.
-p2 = 2p2cosθ.
cosθ = -1/2.
θ = 120.
Tushar Chakraborty said:
10 years ago
Law of Cosine- R^2=P^2+Q^2-2PQ Cosθ
So θ = 60°
When Forces are Nose to tail, θ = 60°
When Forces are Tail to Tail, θ = 180°-60° = 120°
So θ = 60°
When Forces are Nose to tail, θ = 60°
When Forces are Tail to Tail, θ = 180°-60° = 120°
Shams said:
10 years ago
The angle is 60 and not 120. It can be clearly understood from equilateral triangle and total angle in a triangle. And also from the cosine rule: A^2 = B^2+C^2-2BC cosA.
Musliu said:
10 years ago
The correct answer is 120 bc the magnitude re the same.
So therefore R = P the Law of cosine R^2 = R^2 +R^2 - 2R*R (Cosθ).
R^2 - 2 R^2 = - 2R^2COSθ.
- R^2/R^2 = - 2COSθ.
1/2 = COSθ.
Cos^-10.5 = y.
y = 120.
So therefore R = P the Law of cosine R^2 = R^2 +R^2 - 2R*R (Cosθ).
R^2 - 2 R^2 = - 2R^2COSθ.
- R^2/R^2 = - 2COSθ.
1/2 = COSθ.
Cos^-10.5 = y.
y = 120.
Hamed said:
9 years ago
2 x p x cos 120 = R.
p = R.
p = R.
Ankit ughade said:
9 years ago
For getting the equilibrium condition all these forces must have the same angle to each other.
Hence 360/3 = 120.
Hence 360/3 = 120.
P.Chilambarasan said:
9 years ago
R^2 = P^2 + q^2 + 2pq Cosθ.
R = P = Q = F.
Substitute F in the equation, you get Cosθ = -1.
So, θ = 180°.
R = P = Q = F.
Substitute F in the equation, you get Cosθ = -1.
So, θ = 180°.
Dhanendra said:
9 years ago
Correct answer will be 60θ as in fcosθ plus fcosθ equal to f which gives θ equal to 60θ.
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