Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 1 (Q.No. 6)
6.
The velocity ratio in case of an inclined plane inclined at angle θ to the horizontal and weight being pulled up the inclined plane by vertical effort is
Discussion:
58 comments Page 6 of 6.
Naveen said:
1 decade ago
Application of the formula is in the car in the sloping area.
Haryhor. said:
1 decade ago
@Bibin S.
Velocity Ratio can be defined as the ratio of distance moved by effort to the distance moved by load.
Velocity Ratio can be defined as the ratio of distance moved by effort to the distance moved by load.
Bibin S said:
1 decade ago
What is velocity ratio?
Sauvik said:
1 decade ago
As effort has been applied vertically , hence displacement is calculated along the direction of force. Considering the mass does not get detached from the inclined plane, the mass is constrained to move along the inclined plane. Therefore displacement along the hypotenuse would be 1 unit( considering a triangle of 1 unit hypotenuse). Consequently, displacement along the effort would be sin(theta). VR= displacement by effort/ displacement by load, = sin(theta).
Its the same as screw thread principle.
Its the same as screw thread principle.
Nitya said:
1 decade ago
Velocity ratio is the ratio of distance moved by effort to distance moved by force, in case a weight is pulled using a pulley the vertical side is the distance moved by effort, the inclined side is the distance moved by the force.
Chetan said:
1 decade ago
What are the cases for which velocity ratio is being asked?
Soujanya said:
1 decade ago
What is velocity ratio here?
Shiva rao said:
1 decade ago
Opposite side= sinθ.
Base= cosθ.
Because opp.side/hypo=sinθ(hypo=1).
sin2θ+cos2θ=1.
Base= cosθ.
Because opp.side/hypo=sinθ(hypo=1).
sin2θ+cos2θ=1.
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