Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 1 (Q.No. 6)
6.
The velocity ratio in case of an inclined plane inclined at angle θ to the horizontal and weight being pulled up the inclined plane by vertical effort is
Discussion:
58 comments Page 5 of 6.
Azonga Farelle said:
8 years ago
I think the correct answer is tan θ.
Ravi said:
8 years ago
What is velocity ratio here?
A.G.Kesavasekaran said:
8 years ago
Due to the effort the block moves up the inclined plane.
Due to the effort the velocity created along the plane is v.
Velocity created due to vertical effort is v siny.
Therefore VR {vertical effort to effort} = siny.
Due to the effort the velocity created along the plane is v.
Velocity created due to vertical effort is v siny.
Therefore VR {vertical effort to effort} = siny.
Ramesh said:
8 years ago
A is the right answer. I agree.
Saifullah Khan Afridi said:
8 years ago
distance moved by effort= hyp.sinθ
distance moved by load= hyp
V.R= distance moved by effort/distance moved by load
V.R= sinθ.
distance moved by load= hyp
V.R= distance moved by effort/distance moved by load
V.R= sinθ.
SAta said:
8 years ago
Velocity ratio of an inclined plane= cosecθ.
Option D is correct.
Option D is correct.
Prashant said:
8 years ago
Option B is the correct answer.
Suresh Srinivasalu said:
7 years ago
Velocity ratio=height of inclined plane/length of the inclined plane,
= h/l,
= sin(θ).
= h/l,
= sin(θ).
(8)
Akash said:
7 years ago
It is Displacement/distance.
Venkata sai kumar said:
7 years ago
The inclined weight should transform to the vertical and horizontal axis.
The inclined plane makes θ with the horizontal axis.
Then weight on x axis= wcosθ.
Weighht on y axis= wsinθ.
Velocity ratio= wsinθ/wcosθ.
= Tanθ.
The inclined plane makes θ with the horizontal axis.
Then weight on x axis= wcosθ.
Weighht on y axis= wsinθ.
Velocity ratio= wsinθ/wcosθ.
= Tanθ.
(1)
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