Mechanical Engineering - Engineering Mechanics - Discussion

Discussion Forum : Engineering Mechanics - Section 1 (Q.No. 9)
9.
A body of weight W is required to move up on rough inclined plane whose angle of inclination with the horizontal is α. The effort applied parallel to the plane is given by(where μ = tanφ = Coefficient of friction between the plane and the body.)
P = W tanα
P = W tan(α + φ)
P = W (sinα + μcosα)
P = W (cosα + μsinα)
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
21 comments Page 2 of 3.

Saddam husain said:   1 decade ago
From free body diagram,

p = u*R+w*sina.
p = u*(w*cosa)+wsina.
p = w(ucosa+sina).

Rambo said:   7 years ago
Can someone explain how sin, cos and tan is applied? Please tell me.

Tanu said:   9 years ago
What is free body diagram? Please explain.

Manishankar said:   9 years ago
Anyone provide me, its free body diagram.

Ashif said:   8 years ago
Why not?

F=W tan (π+ α).

Fashir said:   7 years ago
Explanations are good. Thanks all.

K. Ajaykumar said:   5 years ago
Thanks all for explaining.

Raghu said:   9 years ago
Thanks for your guidance.

Ahsan said:   6 years ago
Thanks @Saddam Husain.
(1)

Yogesh patel said:   9 years ago
Thanks for guiding me.


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