Logical Reasoning - Number Series - Discussion
Discussion Forum : Number Series - Type 2 (Q.No. 2)
Directions to Solve
Look carefully for the pattern, and then choose which pair of numbers comes next.
2.
8 11 21 15 18 21 22
Answer: Option
Explanation:
This is an alternating addition series, with a random number, 21, interpolated as every third number. The addition series alternates between adding 3 and adding 4. The number 21 appears after each number arrived at by adding 3.
Discussion:
66 comments Page 2 of 7.
Siva said:
1 decade ago
What is your confusion boss it is easy to get because hare to first number first 3 is added and then as third number interpolation would come and then what is there before interpolation number that would be added by 4 like this it will be go on.
Sundar said:
1 decade ago
8 11 [21] 15 18 [21] 22 25 [21] 29 32 [21] 36 39 [21] 43 46 [21] ....
Here 3, 4 is added alternatively and [21] injected as given below:
Inital = 8
8 + 3 = 11
********** [21]
11 + 4 = 15
15 + 3 = 18
********** [21]
18 + 4 = 22
22 + 3 = 25 <----- Required Answer
********** [21] <----- Required Answer
25 + 4 = 29
29 + 3 = 32
.........etc
Here 3, 4 is added alternatively and [21] injected as given below:
Inital = 8
8 + 3 = 11
********** [21]
11 + 4 = 15
15 + 3 = 18
********** [21]
18 + 4 = 22
22 + 3 = 25 <----- Required Answer
********** [21] <----- Required Answer
25 + 4 = 29
29 + 3 = 32
.........etc
Priya said:
1 decade ago
Among all the above solution, I think Sundar is right.
Azhar said:
1 decade ago
Good explained by Sundar.
Bharat said:
1 decade ago
Thanks Sundar.
Vipin said:
1 decade ago
Great job sundar.
Navjot said:
1 decade ago
8,11,[21],15,18,[21],22,25,[21],29,32,[21]
1st no is 8,when 7 is added ,it gives 15 (4th number in series)
2nd no is 11 ,again when 7 is added,it gives 18(5th no in series)
21 is interpolated as every 3rd no.
4th no is 15 ,when 7 is added,it gives 22 (7th no)
5th no is 18,when 7 is added,it gives 25 (8th no)
again 21 is interpolated as 3rd no (here its 6th).
7th no is 22 ,when 7 is added,it gives 29 (10th no)
8th no is 25,when 7 is added,it gives 32 (11th no)
again 21 is interpolated as 3rd no (here its 9th).and so on.....
1st no is 8,when 7 is added ,it gives 15 (4th number in series)
2nd no is 11 ,again when 7 is added,it gives 18(5th no in series)
21 is interpolated as every 3rd no.
4th no is 15 ,when 7 is added,it gives 22 (7th no)
5th no is 18,when 7 is added,it gives 25 (8th no)
again 21 is interpolated as 3rd no (here its 6th).
7th no is 22 ,when 7 is added,it gives 29 (10th no)
8th no is 25,when 7 is added,it gives 32 (11th no)
again 21 is interpolated as 3rd no (here its 9th).and so on.....
Shankari said:
1 decade ago
Really great, I can understand sundar's explanation thank you.
Sudhakar said:
1 decade ago
Actually it would be 25, 29. Adding 3 and alternate adding 4. So it should come 25, 29.
Simarpreet kaur said:
1 decade ago
I am not able to understand it please explain it as a layman could understand.
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