Logical Reasoning - Number Series - Discussion
Discussion Forum : Number Series - Type 2 (Q.No. 1)
Directions to Solve
Look carefully for the pattern, and then choose which pair of numbers comes next.
1.
28 25 5 21 18 5 14
Answer: Option
Explanation:
This is an alternating subtraction series with the interpolation of a random number, 5, as every third number. In the subtraction series, 3 is subtracted, then 4, then 3, and so on.
Discussion:
128 comments Page 13 of 13.
Vaidik said:
9 months ago
@All.
Here, the First number will be 11 and the second number will be 7, need to check the options once again.
Correct me, If I am wrong.
Here, the First number will be 11 and the second number will be 7, need to check the options once again.
Correct me, If I am wrong.
(4)
Inapakurthi dinesh said:
8 months ago
@Hema.
Thanks for the clarification.
Thanks for the clarification.
(4)
Suryanshu agrawal said:
8 months ago
Thanks all for explaining the answer.
(7)
Sk ali said:
6 months ago
28-3 = 25,
25-4 = 21,
21-3 = 18,
18-4 = 14,
14-3 = 11 ( 5 is a random number).
25-4 = 21,
21-3 = 18,
18-4 = 14,
14-3 = 11 ( 5 is a random number).
(22)
Sommit said:
5 months ago
Thanks everyone for explaining the answer.
(3)
Ammu said:
5 months ago
Thanks for these questions, it is very useful for me.
(7)
CHAUDHARI SATISH said:
3 weeks ago
5 is random 11 & 5 is right Answer.
28-3 = 25 then 5.
25-4=21 then 5.
21-3= 18 then 5.
18-4= 14.
14-3= 11 then 5.
So, 28 25 5 21 18 5 14 11 5 this series.
28-3 = 25 then 5.
25-4=21 then 5.
21-3= 18 then 5.
18-4= 14.
14-3= 11 then 5.
So, 28 25 5 21 18 5 14 11 5 this series.
(1)
Billa said:
1 week ago
Given sequence.
28 25 5 | 21 18 5 | 14 ? ?
28 − 25 = 3 → 3 + 2 = 5,
21 − 18 = 3 → 3 + 2 = 5,
14 − 11 = 3 → 3 + 2 = 5.
First number − second number = 3.
Then 3 + 2 = 5.
Finally
After 14, the next number must be 11, and then 5.
28 25 5 | 21 18 5 | 14 ? ?
28 − 25 = 3 → 3 + 2 = 5,
21 − 18 = 3 → 3 + 2 = 5,
14 − 11 = 3 → 3 + 2 = 5.
First number − second number = 3.
Then 3 + 2 = 5.
Finally
After 14, the next number must be 11, and then 5.
(3)
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