Logical Reasoning - Letter and Symbol Series - Discussion

In the question, there are only three alphabets in sequence B,C,D....The Numbers are also in sequence where the 3rd sequence/number is missing hence BC3D is the answer.

Replace the question with the given answer:
B2CD, (BC3D), BCD4, B5CD, BC6D

Now the numbers are in sequence 2,3,4,5,6...

Hope you got it now guys!

Concentrate on the no's dude first it comes to b then c then d and again started from b, c and so on.

The letters are the same for each case only the no.s 2,3,4....... are moving in cyclic order i.e. from b to c & from c to d and and when one cycle is finished we again go back to the previous one i.e. to B.

watch anusha comments she is giving right answer

The letter are same for each case only no are change in every order for eg. first b2cd then one no increase it make bc3d

Hi guys,

I didnt understand the above logic.

Hi,

In the above quest they are asking for sequential series ok...just concentrate the series in first term b2cd = b+b+c+d(4 letter) in third term i.e bcd4 = b+c+d+d+d+d(total 6 letter)similarly 4th term contain 7 letter and last term contain 8 letter therefore according to series there must be contain 5 letter in 2nd term. now see the option i.e how many option u have that contain 5 letter only two option are there i.e option A & opt B so we go for option B only because no one term contain two word simultaneously more than one times except option B i.e in option A(it contain 5 letter but here two word i.e B,B and C,C simultaneously)thats y we go for option B. this is the right ans.

It is very simple thing letter is same its didn't change but number is in sequence the sequence is 2 3 4 5 6 and in the options b and d contains 3, but in d option it also had 2 so it is not correct option then b is the correct.

Tell me what is logic in this?

In the above question they are asking for sequential series ok. Just concentrate the series in first term B₂CD = B+B+C+D (4 letter) in third term i.e., BCD₄ = B+C+D+D+D+D (total 6 letter) similarly 4th term contain 7 letter and last term contain 8 letter therefore according to series there must be contain 5 letter in 2nd term.

Now see the option i.e., how many option you have that contain 5 letter only two option are there i.e., option A & opt B so we go for option B only because no one term contain two word simultaneously more than one times except option B i.e., in option A (it contain 5 letter but here two word i.e., B, B and C, C simultaneously) thats why we go for option B. This is the right answer.