Logical Reasoning - Letter and Symbol Series - Discussion
Discussion Forum : Letter and Symbol Series - Type 1 (Q.No. 2)
Directions to Solve
In these series, you will be looking at both the letter pattern and the number pattern. Fill the blank in the middle of the series or end of the series.
2.
B2CD, _____, BCD4, B5CD, BC6D
Answer: Option
Explanation:
Because the letters are the same, concentrate on the number series, which is a simple 2, 3, 4, 5, 6 series, and follows each letter in order.
Discussion:
46 comments Page 2 of 5.
Swati said:
9 years ago
Please explain the last term.
(2)
WILLIAMKERY said:
1 decade ago
First number B2CD = B + B + C + D = 4 "B2". First series start with 2.
Second number BC3D = B + C + C + C +D = 5 "C3". Second series Sequence 3.
Third Numbr BCD4 = B + C + D + D + D + D = 6 "D4" Third Series sequence 4.
Fourth Number B5CD = B + B + B + B + B + C + D =7 "B5" Alternator continue with number 5.
Fifth number BC6D =B +C + C + C + C + C + C + D =8 "C6" This the sequence with 6.
Second number BC3D = B + C + C + C +D = 5 "C3". Second series Sequence 3.
Third Numbr BCD4 = B + C + D + D + D + D = 6 "D4" Third Series sequence 4.
Fourth Number B5CD = B + B + B + B + B + C + D =7 "B5" Alternator continue with number 5.
Fifth number BC6D =B +C + C + C + C + C + C + D =8 "C6" This the sequence with 6.
(1)
Prakash said:
10 years ago
Someone please explain me to get the answer.
(1)
Krishna said:
9 years ago
B2CD, -------, BCD4, B5CD, BC6D.
SOLVE,
2+1=3 after one word BC3D.
3+1=4 after one word BCD4.
4+1=5 after one word (repeat from first word because D is end) B5CD.
5+1=6 after one word BC6D.
SOLVE,
2+1=3 after one word BC3D.
3+1=4 after one word BCD4.
4+1=5 after one word (repeat from first word because D is end) B5CD.
5+1=6 after one word BC6D.
(1)
Rubini said:
1 decade ago
Hai friends I got the answer.
Sunil brahmajosyula said:
1 decade ago
Base values are in the order of 4, ---, 6, 7, 8 find the base value of 5 from the options.
Harsha said:
1 decade ago
I can't understand this logic.
Harsha said:
1 decade ago
@Rubini tell me about the your answer.
Surya teja.m said:
1 decade ago
B2CD, _BC3D_, BCD4 = in B2CD B has number 2, in BCD4 D has a number 4 C has no number so answer is BC3D. The series of the number is 2, 3, 4.
B2 has 2 in first set of words, C has missing number so we have entered 3 for C in second set of words i.e., C3, D4 in third set of words.
B2 has 2 in first set of words, C has missing number so we have entered 3 for C in second set of words i.e., C3, D4 in third set of words.
GOMATHI said:
10 years ago
On this letter series the number will take b to c, and c to d, and again d to b like triangle wise. So first, b series they had been mentioned the substring of 2. So, what will happen, next to b, c series will get the next process, after that d, next c.
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