Java Programming - Threads - Discussion
Discussion Forum : Threads - Finding the output (Q.No. 4)
4.
What will be the output of the program?
class s1 implements Runnable
{
int x = 0, y = 0;
int addX() {x++; return x;}
int addY() {y++; return y;}
public void run() {
for(int i = 0; i < 10; i++)
System.out.println(addX() + " " + addY());
}
public static void main(String args[])
{
s1 run1 = new s1();
s1 run2 = new s1();
Thread t1 = new Thread(run1);
Thread t2 = new Thread(run2);
t1.start();
t2.start();
}
}
Answer: Option
Explanation:
Both threads are operating on different sets of instance variables. If you modify the code of the run() method to print the thread name it will help to clarify the output:
public void run(){
for(int i = 0; i < 10; i++)
System.out.println(
Thread.currentThread().getName() + ": " + addX() + " " + addY()
);
}
Discussion:
13 comments Page 2 of 2.
Srirajyalakshmi said:
1 decade ago
I did not understand the logic can any one explain please.
Raghu said:
9 years ago
I cannot understand the program please explain in detail.
Saurabh garg said:
1 decade ago
I did not understand the reason. Can anyone explain.
Post your comments here:
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