IndiaBIX

Java Programming - Threads - Discussion

Discussion Forum : Threads - Finding the output (Q.No. 15)
Threads
15.
What will be the output of the program? 
public class ThreadTest extends Thread 
{ 
    public void run() 
    { 
        System.out.println("In run"); 
        yield(); 
        System.out.println("Leaving run"); 
    } 
    public static void main(String []argv) 
    { 
        (new ThreadTest()).start(); 
    } 
}
The code fails to compile in the main() method
The code fails to compile in the run() method
Only the text "In run" will be displayed
The text "In run" followed by "Leaving run" will be displayed
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
13 comments Page 2 of 2.
Anonymous said:   1 decade ago
Output will be :

In run.
Leaving run.

Its fine for compilation, just because calling yield() inside run().
Kratika said:   9 years ago
Yield method only delays the current thread for some time or can it shift the priority.
Sudhansu said:   1 decade ago
yield() is a static method . Thes how we are invoking it for an instance using this.
Post your comments here:

Your comments will be displayed after verification.

Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers