Java Programming - Operators and Assignments - Discussion

Discussion Forum : Operators and Assignments - Finding the output (Q.No. 3)
3.
What will be the output of the program?
class PassS 
{
    public static void main(String [] args) 
    {
        PassS p = new PassS();
        p.start();
    }

    void start() 
    {
        String s1 = "slip";
        String s2 = fix(s1);
        System.out.println(s1 + " " + s2);
    }

    String fix(String s1) 
    {
        s1 = s1 + "stream";
        System.out.print(s1 + " ");
        return "stream";
    }
}
slip stream
slipstream stream
stream slip stream
slipstream slip stream
Answer: Option
Explanation:

When the fix() method is first entered, start()'s s1 and fix()'s s1 reference variables both refer to the same String object (with a value of "slip"). Fix()'s s1 is reassigned to a new object that is created when the concatenation occurs (this second String object has a value of "slipstream"). When the program returns to start(), another String object is created, referred to by s2 and with a value of "stream".

Discussion:
30 comments Page 3 of 3.

Sathis said:   1 decade ago
What is system.out.format(); if I use this function what package should I use?

Shweta said:   1 decade ago
String is immutable then why s1 = s1 + "stream" is not giving any error.

Karthik said:   1 decade ago
What is the difference between system.out.print and system.out.println?

Vinod said:   1 decade ago
I can't understand the flow can anyone explain in detail?

Yuvaraj said:   1 decade ago
No Java Does Not Support multiple inheritance.

Likki said:   9 years ago
Thanks you all for giving the explanation.

Rajesh Jaiswal said:   1 decade ago
Is java support multiple inheritance?

Clinton g said:   10 months ago
I got it now, clearly.

Subhashini said:   6 years ago
Thank you @Siddu.
(1)

Mohanapriya said:   6 years ago
Thank you all.
(1)


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