Java Programming - Operators and Assignments - Discussion

String Class is Immutable in Java.

So whenever we are concatenate a string object a new String object is created.

s1>>>>>>>>>Slip.

A method local s1 in fix method s1>>>>>>Slip Stream.

s2>>>>>>stream.

class PassS
{
public static void main(String [] args)
{
PassS p = new PassS();
p.start();
}

void start()
{
String s1 = "slip";
String s2 = fix(s1);
System.out.println(s1 + " " + s2); //line 13
}

String fix(String s1)
{
s1 = s1 + "stream";
System.out.print(s1 + " ");
return "stream";
}
}

See line 13.

System.out.println(s1 + " " + s2);

Slipstream slip stream.

The word slip in between is due to the s1 variable in line 13.

There are two print statements:

System.out.print(s1 + " "); //prints slipstream.
System.out.println(s1 + " " + s2); // prints slip stream.

I can't understand the flow can anyone explain in detail?

How is the slip coming between slipstream and stream? I don't understand. Please explain anyone in details?

Option B should be the answer, as it does not give us the explanation about the slip placed in between. And even before that my logic say fix method return the value of s1 as slip stream (s1 = s1 + "stream";) an return statement return stream to s2. And then the o/p is shown.

What is system.out.format(); if I use this function what package should I use?

I am not getting the point. And can't understand how to solve this kind of problem. Its answer is right but output is logically different from the previous question.

Because of the s1 object created with new string means s1 gets modified value in fix() and it return to start(),

Then again s1 modified & new object created and stored in s2.

In the case of slip stream(string), why is that the change of s1 in stringfix() not reflected on to the s1 in start() ?

@Remya : Remember array is an Object in Java whereas Boolean is just a variable.