Java Programming - Operators and Assignments - Discussion
Discussion Forum : Operators and Assignments - Finding the output (Q.No. 7)
7.
What will be the output of the program?
class Test
{
public static void main(String [] args)
{
int x= 0;
int y= 0;
for (int z = 0; z < 5; z++)
{
if (( ++x > 2 ) && (++y > 2))
{
x++;
}
}
System.out.println(x + " " + y);
}
}
Answer: Option
Explanation:
In the first two iterations x is incremented once and y is not because of the short circuit && operator. In the third and forth iterations x and y are each incremented, and in the fifth iteration x is doubly incremented and y is incremented.
Discussion:
30 comments Page 2 of 3.
Vinoth said:
1 decade ago
I'm still confusing because "if" condition is failed then the x would not be incremented, It would come out from the loop. Explain me please?
Niharika patidar said:
6 years ago
Please explain to me.
What is the reason that ++y is not executed for the first two times?
What is the reason that ++y is not executed for the first two times?
(1)
Sushaja said:
3 years ago
@Arnold.
Thank you for explaining the short circuit operator's operation in detail.
Thank you for explaining the short circuit operator's operation in detail.
Unknown said:
6 years ago
output of int z=2; while(z<20) if((z++)%2==0) system.out.println(z);
Peacz said:
10 years ago
@Uma you can see @Narayana Murthy explain.
He explain so clear.
He explain so clear.
Magesh said:
2 decades ago
Can any one please mention what is short circuit operator?
Aashish said:
9 years ago
Thanks for your explanation @Arnold Villasanta.
Sunny deol said:
9 years ago
Now I understand this, thank you @Nataliia.
Preethi said:
7 years ago
Thank you good explanation @G.Vivekananda.
Aparna said:
7 years ago
Hi, Please explain this problem using OR.
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