Java Programming - Java.lang Class - Discussion
Discussion Forum : Java.lang Class - Finding the output (Q.No. 5)
5.
What will be the output of the program?
public class Example
{
public static void main(String [] args)
{
double values[] = {-2.3, -1.0, 0.25, 4};
int cnt = 0;
for (int x=0; x < values.length; x++)
{
if (Math.round(values[x] + .5) == Math.ceil(values[x]))
{
++cnt;
}
}
System.out.println("same results " + cnt + " time(s)");
}
}
Answer: Option
Explanation:
Math.round() adds .5 to the argument then performs a floor(). Since the code adds an additional .5 before round() is called, it's as if we are adding 1 then doing a floor(). The values that start out as integer values will in effect be incremented by 1 on the round() side but not on the ceil() side, and the noninteger values will end up equal.
Discussion:
11 comments Page 2 of 2.
John said:
8 years ago
First Loop:
(x=0; 0<4; x++) // true.
(-2.3 plus 0.5) with round function = -2 == (-2.3) with ceiling function = -2.0.
-2 == -2.0 = True so cnt =1.
Second Loop:
(x=1; 1<4; x++) // true
(-1.0 plus 0.5) with round function = 0 == (-1.0) with ceiling function = -1.0.
0 == -1.0 = False so cnt =1.
Third Loop:
(x=2; 2<4; x++) // true
(0.25 plus 0.5) with round function = 1 == (0.25) with ceiling function is 1.0.
1 == 1.0 = True, so cnt=2.
Fourth Loop:
(x=3; 3<4; x++) // true
(4.0 plus 0.5) with round function = 5 == (4.0) with ceiling function is 4.0.
5 == 4 = False, so cnt=2.
Fifth Loop:
(x=4; 4<4; x++) // false ( 4<4 ) so, loop finish.
Print: same results 2 time(s).
(x=0; 0<4; x++) // true.
(-2.3 plus 0.5) with round function = -2 == (-2.3) with ceiling function = -2.0.
-2 == -2.0 = True so cnt =1.
Second Loop:
(x=1; 1<4; x++) // true
(-1.0 plus 0.5) with round function = 0 == (-1.0) with ceiling function = -1.0.
0 == -1.0 = False so cnt =1.
Third Loop:
(x=2; 2<4; x++) // true
(0.25 plus 0.5) with round function = 1 == (0.25) with ceiling function is 1.0.
1 == 1.0 = True, so cnt=2.
Fourth Loop:
(x=3; 3<4; x++) // true
(4.0 plus 0.5) with round function = 5 == (4.0) with ceiling function is 4.0.
5 == 4 = False, so cnt=2.
Fifth Loop:
(x=4; 4<4; x++) // false ( 4<4 ) so, loop finish.
Print: same results 2 time(s).
(1)
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