Java Programming - Flow Control - Discussion
Discussion Forum : Flow Control - Finding the output (Q.No. 4)
4.
What will be the output of the program?
public class SwitchTest
{
public static void main(String[] args)
{
System.out.println("value =" + switchIt(4));
}
public static int switchIt(int x)
{
int j = 1;
switch (x)
{
case l: j++;
case 2: j++;
case 3: j++;
case 4: j++;
case 5: j++;
default: j++;
}
return j + x;
}
}
Answer: Option
Explanation:
Because there are no break statements, once the desired result is found, the program continues though each of the remaining options.
Discussion:
14 comments Page 2 of 2.
Shreyas singh said:
9 years ago
I think it's been initiating from case 4, so on case 4 j=2, case 5 j=3, default case j=4, so now we have value of x as 4, at the end its been said to add this two, so x+j =8.
(1)
Venky said:
6 years ago
Nice, thanks for explaining.
Venkatesh said:
6 years ago
The default case value of j=3.
Once it comes out of switch case post-increment of j is there (i.e. Value of j=3 but j++ is there so j becomes 4.
So finally value will be x+j = 4+4 = 8.
So the answer will be 8.
Once it comes out of switch case post-increment of j is there (i.e. Value of j=3 but j++ is there so j becomes 4.
So finally value will be x+j = 4+4 = 8.
So the answer will be 8.
(2)
Anukirti said:
5 years ago
How int j =1; is valid as we cannot declare any local variable inside a static method?
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