Java Programming - Flow Control - Discussion

Discussion Forum : Flow Control - Finding the output (Q.No. 3)
3.
What will be the output of the program?
public class Switch2 
{
    final static short x = 2;
    public static int y = 0;
    public static void main(String [] args) 
    {
        for (int z=0; z < 3; z++) 
        {
            switch (z) 
            {
                case x: System.out.print("0 ");
                case x-1: System.out.print("1 ");
                case x-2: System.out.print("2 ");
            }
        }
    }
}
0 1 2
0 1 2 1 2 2
2 1 0 1 0 0
2 1 2 0 1 2
Answer: Option
Explanation:

The case expressions are all legal because x is marked final, which means the expressions can be evaluated at compile time. In the first iteration of the for loop case x-2 matches, so 2 is printed. In the second iteration, x-1 is matched so 1 and 2 are printed (remember, once a match is found all remaining statements are executed until a break statement is encountered). In the third iteration, x is matched. So 0 1 and 2 are printed.

Discussion:
26 comments Page 3 of 3.

Anshu said:   1 decade ago
Why we check the conditions from last but not from first?

Ram said:   1 decade ago
Is it necessary to declare x as final?

Anjena said:   1 decade ago
Can you explain about final keyword?

Priya said:   1 decade ago
Great! I understand Raju. Thanks!

Vasavi said:   6 years ago
Can anyone explain it clearly?

Rahul said:   9 years ago
Nice programming question.


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