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Java Programming - Flow Control - Discussion

Discussion Forum : Flow Control - Finding the output (Q.No. 20)
Flow Control
20.
What will be the output of the program? 
int i = 0, j = 5; 
tp: for (;;) 
    {
        i++;  
        for (;;) 
        {
            if(i > --j) 
            {
                break tp; 
            } 
        } 
        System.out.println("i =" + i + ", j = " + j);
i = 1, j = 0
i = 1, j = 4
i = 3, j = 4
Compilation fails.
Answer: Option
Explanation:

If you examine the code carefully you will notice a missing curly bracket at the end of the code, this would cause the code to fail.

Discussion:
17 comments Page 2 of 2.
Gaurav said:   1 decade ago
How can j = 0, because when break up run it will print the sop statement.

i.e. i = 1, j = 4.
Mehul said:   1 decade ago
If curly brackets would have been there in corrrect pos then answer would be i= 1 and j=0.
Vishesh said:   1 decade ago
If curly braces of for ended before println then it print i=1 and j=0.
Jhon said:   1 decade ago
There is no main method which is to be noticed.
PleaseBugMeNot said:   1 decade ago
TP represents as label for the loop.
Aravindh said:   1 decade ago
What is tp: kindly explain me ?
Vikas said:   10 years ago
What is tp doing with break?
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