Java Programming - Exceptions - Discussion
Discussion Forum : Exceptions - Finding the output (Q.No. 10)
10.
What will be the output of the program?
class Exc0 extends Exception { }
class Exc1 extends Exc0 { } /* Line 2 */
public class Test
{
public static void main(String args[])
{
try
{
throw new Exc1(); /* Line 9 */
}
catch (Exc0 e0) /* Line 11 */
{
System.out.println("Ex0 caught");
}
catch (Exception e)
{
System.out.println("exception caught");
}
}
}
Answer: Option
Explanation:
An exception Exc1 is thrown and is caught by the catch statement on line 11. The code is executed in this block. There is no finally block of code to execute.
Discussion:
11 comments Page 2 of 2.
Parikrma said:
1 decade ago
Why it gives error when we are changing catch block's order ?
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