General Knowledge - Physics - Discussion

Discussion Forum : Physics - Section 1 (Q.No. 23)
23.
Find the maximum velocity for the overturn of a car moving on a circular track of radius 100 m. The co-efficient of friction between the road and tyre is 0.2
0.14 m/s
140 m/s
1.4 km/s
14 m/s
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
46 comments Page 5 of 5.

Nikhil said:   1 decade ago
As the S.I unit of acceleration is m/s.

Bhavana said:   1 decade ago
Maximum velocity of car = coefficient of friction X radius X acceleration due to gravity.
= 0.2X 100X 9.8.
=14m/s.

Joshi said:   1 decade ago
v=mu*r*g is the correct formula.

Deep said:   1 decade ago
Where this formula is given?

Pablo said:   1 decade ago
But max speed can be 140m/sec. Because even it will result in the overturn.

Gerald said:   1 decade ago
Can someone who knows this make it clear to us please.


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