General Knowledge - Physics - Discussion
Discussion Forum : Physics - Section 1 (Q.No. 23)
23.
Find the maximum velocity for the overturn of a car moving on a circular track of radius 100 m. The co-efficient of friction between the road and tyre is 0.2
Discussion:
46 comments Page 5 of 5.
Rishabh said:
1 decade ago
9. 8 where it came from?
Mukuuuuu champ physics said:
1 decade ago
tan$=v2/rg
tan$=miu
sqrtrgmiu=velocity
tan$=miu
sqrtrgmiu=velocity
Sanjay said:
1 decade ago
Can I know how this formula has been derived?
125 said:
1 decade ago
(co-efficient of friction X radius X acceleration due to gravity).
Can I know how this formula has been derieved.
Can you please explain this formula?
Can I know how this formula has been derieved.
Can you please explain this formula?
Amit bole said:
1 decade ago
But the distance covered by the car is the circumference of a circle.
Sayyed Toufique Ali said:
1 decade ago
The maximum speed for the overturn of a car moving on a circular track is given by,
v=underroot(co-efficient of friction X radius X acceleration due to gravity)
v=underroot(0.2 X 100 X 9.8)
v=14m/s.
v=underroot(co-efficient of friction X radius X acceleration due to gravity)
v=underroot(0.2 X 100 X 9.8)
v=14m/s.
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