General Knowledge - Physics - Discussion
Discussion Forum : Physics - Section 1 (Q.No. 23)
23.
Find the maximum velocity for the overturn of a car moving on a circular track of radius 100 m. The co-efficient of friction between the road and tyre is 0.2
Discussion:
46 comments Page 4 of 5.
Kailas said:
9 years ago
Thanks to everyone. Really helpful explanation.
Antim said:
9 years ago
Centrifugal force = Friction force,
mv^2/r = friction * mg.
mv^2/r = friction * mg.
Josephine said:
9 years ago
Thanks for all your good work. It is really helpful.
Ihsan ullah said:
9 years ago
Thanks to everyone. Really helpful explanation.
Ahmad said:
9 years ago
Forces required to move a car in a circular track?
A. Centripetal force
B. Friction
C. Both
D. None
Answer the question.
A. Centripetal force
B. Friction
C. Both
D. None
Answer the question.
(1)
Ahmad said:
9 years ago
Can a car move without friction?
Sai manoj said:
8 years ago
It's very simple sum because
Velocity(V) = ?.
Radius(R) = 100m,
Co-efficient of friction(f) = 0.2,
Gravitational force(g) = 9.8.
V=F * V * G.
V^2=0.2 * 100 * 9.8 = 196underroot,
v = root 196,
V = 14m/s.
Velocity(V) = ?.
Radius(R) = 100m,
Co-efficient of friction(f) = 0.2,
Gravitational force(g) = 9.8.
V=F * V * G.
V^2=0.2 * 100 * 9.8 = 196underroot,
v = root 196,
V = 14m/s.
(3)
M.sathvik said:
8 years ago
Option C is the correct answer.
(1)
Kriti said:
8 years ago
Yes, I agree @M. Sathvik.
Jasbir Ranga said:
8 years ago
Yes, I agree @Sayyad Touffiq Ali.
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