General Knowledge - Physics - Discussion

Discussion Forum : Physics - Section 1 (Q.No. 23)
23.
Find the maximum velocity for the overturn of a car moving on a circular track of radius 100 m. The co-efficient of friction between the road and tyre is 0.2
0.14 m/s
140 m/s
1.4 km/s
14 m/s
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
46 comments Page 2 of 5.

Pawan said:   1 decade ago
If we substitute the given values in (co-efficient of friction X radius X acceleration due to gravity) , we will get the answer as 196 but not 14. I think there is formula related to friction from the above problem.

Abhi said:   1 decade ago
@Pawan.

Can't you see there is a underroot written in the formula? underroot 196 = 14.

Sara said:   1 decade ago
Force of friction is equal to required centripetal force to move the body in circular path. Equate both forces as,

mu m g = m v*2 /r.
Cancelling mass on both sides we get the formula of velocity by simplifying as,

V= sq root mu r g.

Prajakta Patil said:   1 decade ago
Because there is one formula for max. velocity i.e.

V.V = urg.

Where u=coefficient of friction of that road.
r=radius of road.
g=acceleration due to gravity,which is on the earth equal to 9.8 m/s.

Pankaj pundir said:   1 decade ago
If it travel in circular motion it affected by two forces centripetal force and gravitational force expression.

mg = mv(sq)/r.

Abiha said:   1 decade ago
v2 = {co-efficient of friction X radius X acceleration due to gravity).

v2 = {0.2 x 100 x 9.8}.
= 196.

v = 14m/sec.

Nikhil said:   1 decade ago
As the S.I unit of acceleration is m/s.

Amisha said:   1 decade ago
r = 100
v = ?
coefficient of friction = ?

As v = underroot(coefficient of friction X radius X acceleration due to gravity).
v = underroot (0.2 X 100 X 9.8).
v = 14m/s.

Bhavana said:   1 decade ago
Maximum velocity of car = coefficient of friction X radius X acceleration due to gravity.
= 0.2X 100X 9.8.
=14m/s.

Joshi said:   1 decade ago
v=mu*r*g is the correct formula.


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