Electronics - Voltage and Current - Discussion
Discussion Forum : Voltage and Current - General Questions (Q.No. 9)
9.
In practical applications, battery voltage:
Discussion:
45 comments Page 2 of 5.
Swapnajit said:
1 decade ago
According to ohms law voltage is directly to propotional to current.
V= IR.
As as "R" increases so I will be less for const voltage supply. I less means we less (directly propotional).
V= IR.
As as "R" increases so I will be less for const voltage supply. I less means we less (directly propotional).
Sharma said:
1 decade ago
When in our home we switch on many heavy electrical devices simultaneously then automatically the tube lights get dim. And that is only due to the dropping of voltage. That's it. :).
Eshwar said:
1 decade ago
Power= Voltage*current
Increase in Load means Increase in load current.
So if Current increases, Voltage has to be decreased so that total power remains constant( V*I= constant).
Increase in Load means Increase in load current.
So if Current increases, Voltage has to be decreased so that total power remains constant( V*I= constant).
Nilesh said:
1 decade ago
If the resistance increase then gragually current decerease. So that think logically that whn resistance increase thn load incerase in the wire so rate of current is to be slow.
Pradeep raj said:
1 decade ago
Inductor it is a bulky component and it is responsible for magnetic field usually units are HenrY.
WHEREAS CAPACITOR is skinny and it is responsible electric field.
WHEREAS CAPACITOR is skinny and it is responsible electric field.
Ahi said:
1 decade ago
Its very easy. You just think about your mobile when you call or receive more [load] then your power, that is your battery will automatically decrease.
Pongo said:
1 decade ago
V is proportional to I means V/I=constant. Again, V=IR or, V/I=R. So if the load R increases and keep the current constant, then V also increases.
Sreeyush Sudhakaran said:
1 decade ago
Consider you as battery and load as sack lifted by you
When ever number of sacks(Load) increases your energy(battry voltage) decreses gradually.
When ever number of sacks(Load) increases your energy(battry voltage) decreses gradually.
NKR said:
1 decade ago
V=IR...In that v proportional to I. so as load increases current decreases through the R. Then voltage decreases because v proportional to I
Gaurav said:
1 decade ago
For ideal constant voltage source, voltage willnot change. But in practical it decreses as load increases. And power need to be constant.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers